a. A’ ⊂ A and R’ = R ∩ (A’ x A’) |
b. A’ ⊂ A and R ⊂ R’ ∩ (A’ x A’) |
c. R’ = R ∩ (A’ x A’) |
d. A’ ⊆ A and R ⊆ R’ ∩ (A’ x A’) |
Answer: A’ ⊂ A and R’ = R ∩ (A’ x A’) |
a. A’ ⊂ A and R’ = R ∩ (A’ x A’) |
b. A’ ⊂ A and R ⊂ R’ ∩ (A’ x A’) |
c. R’ = R ∩ (A’ x A’) |
d. A’ ⊆ A and R ⊆ R’ ∩ (A’ x A’) |
Answer: A’ ⊂ A and R’ = R ∩ (A’ x A’) |